Re: quality control
- From: "Frank" <deps_bear@xxxxxxxxx>
- Date: 12 Nov 2006 21:38:26 -0800
Richard, thanks for your reply, however checking 1400 out of the 1500
items does not seem like a cost-effective approach. I may not have
phrased the question correctly and also did some additional research.
I'm thinking with the binary outcome of fail/not fail, then this is
more of just a sampling question and knowing there are 1500 items is
irrelevant. So, if I suspect that 1% of the items fail, and put a
confidence interval around this estimate with a width of plus/minus 10%
(that is, the interval would go from .09% to 1.1%), then I would need
to sample 38 with 95% confidence. That is, I can say that my sample of
38 will contain 1% of the proportion that fails 95% of the time.
Richard Ulrich wrote:
On 12 Nov 2006 17:00:04 -0800, "Frank" <deps_bear@xxxxxxxxx> wrote:
If I know a product fails .01% of the time and I have 1500 items I'm
running through a process. How many items do I need to check with,
say, 99% confidence that all the items are built correctly.
How many failures do you expect? Almost always, zero.
This is dealing with exact probabilities. For a higher failure
rate, you might want to look at the p of success, and raise
to a power, e.g., (.9999)^n . For the tiny p of 0.01%,
the figuring can be pretty much additive
You want to have only so many items *unchecked* that there
will be, on the average, only 1 bad item in 100 samplings --
so that 99 times out 100, there will be none.
You expect 1 failure in 10,000. One hundred samplings
that each fail to test 100 items will meet that condition.
So you need to check 1400 of each 1500.
--
Rich Ulrich, wpilib@xxxxxxxx
http://www.pitt.edu/~wpilib/index.html
.
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