Re: Simple binomial test question
- From: Jack Tomsky <jtomsky@xxxxxxxxxxxxx>
- Date: Thu, 26 Apr 2007 12:22:19 EDT
Hi, very simple I know, but just want to check that I
think correctly.
the problem:
"A coin is tossed 10 times and 2 heads are obtained.
Test Weather the coin
is biased."
So Definitely we are using binomial distribution,
isnt it? so
null hypothesis: "We get 5 heads"
alternative hypothesis: "head number<>5"
The null and alternative hypotheses have to be expressed in terms of the unknown probability of a head, p, and not the sample statistics. Thus,
H: p = 0.5 is tested against K: p not equal to 0.5.
The wording of the question suggests that the alternative hypothesis should be two-sided.
So its gonna be 2-tailed test. So if I calculate
propabilities to get 0,1,2
and add them I get the test value (which is about
0.054). But using 2-tailed
95% confidence level test, the first tail is located
at 0.025 and the right
tail is at 0.975. Becouse 0.054 is more than 0.025 ,
the null hypothesis
remains, so we cannot say that the coin is biased.
The specified type I error is called the significance level, not the confidence level. You may set significance level at 0.05. Since your calculated p-value of 0.054 exceeds the pre-asssigned significance level, you accept the null hypothesis H.
Intuitively you had the right idea, but you used the wrong terminology.
Jack
.
Did it go ok?? this is how my common sense says it
could be done. We cannot
use poison/normal distributions, couse sample size is
small, isnt it?? We do
2-tailed or one tailed? I am sure 2-tailed, just
checking ...
thanks
- References:
- Simple binomial test question
- From: JPK
- Simple binomial test question
- Prev by Date: Simple binomial test question
- Next by Date: Re: Simple binomial test question
- Previous by thread: Simple binomial test question
- Next by thread: Re: Simple binomial test question
- Index(es):
Relevant Pages
|