Re: anova and chi-square test
- From: David Winsemius <doe_snot@xxxxxxxxxxx>
- Date: Wed, 08 Aug 2007 08:35:19 -0500
Bruce Weaver <bweaver@xxxxxxxxxxxx> wrote in news:1186512446.379964.168920
@d55g2000hsg.googlegroups.com:
On Aug 6, 9:37 pm, Mike <Sulfate...@xxxxxxxxx> wrote:
On Aug 6, 8:30 pm, Tim De Meyer <Tim.DeMe...@xxxxxxxx> wrote:
Hi
I usually confuse anova and chi-square test.
Is there any simple way to tell from?
Mike
Oversimplified (I know!):
anova: variable of interest (dependent) is continuous
chi-square: variable of interest (dependent) is factor
So if the dependent variable is discontinuous, then use chi-square?
The chi-square test of association is used to test the null hypothesis
that there is no association between two nominal scale (categorical)
variables. It requires no distinction between independent and
dependent variables.
No debate on your statement as far as it goes. It is unfortunate, however,
that the tests using the chi-square distribution as their reference have
acquired the label "chi-square" without qualification and without
understanding of the severe limitations of the "test of association". There
are other forms of "chi-square" tests that are be more valuable
(statistically powerful) in specific situations. The chi-square tests of
ordered relationships ("trend tests") are often overlooked in situations
where they would be perfectly valid and far more powerful than the test of
general association.
--
David Winsemius
.
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- Re: anova and chi-square test
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