lognormal-Poisson mean and variance?

Hi everyone,

e.g. (for clarity) if the parameters of a negative binomial
(=gamma-Poisson)
are r and p, then mean = r(1-p)/p variance = r(1-p)/p^2

What are the equivalent expressions for a lognormal-Poisson?

I've looked in all my standard places but can't find it, and the
integration
is well beyond my skills :-(

Thanks in advance
(sorry for the necessary anonymity)

A Lurker


.

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